Heat, Water, Stress.
Soils and rocks are porous: a solid skeleton with fluid in the voids. Heat a saturated ground and the water expands faster than the grains, so pressure rises and the skeleton unloads. Squeeze it and water is driven out. Pump water in and the ground can slip. These are the thermo-hydro-mechanical couplings, and this page builds them up one instrument at a time.
The porous medium
A soil or rock is two things at once: a skeleton of grains or crystals that carries load, and a connected network of voids that stores and transmits fluid. Continuum theories do not follow individual pores. They average over a representative elementary volume: a window large enough that the averaged property stops fluctuating with window size, yet small compared with the distance over which pressure, temperature and stress vary.
The first number that comes out of the averaging is the porosity, the void fraction of the volume. Almost everything else is built on it: the void ratio favoured in soil mechanics, and the mixture rules that give the medium a single heat capacity and thermal conductivity.
\[ n = \frac{V_v}{V},\qquad e = \frac{n}{1-n},\qquad (\rho c)_{\mathrm{eff}} = n\,\rho_w c_w + (1-n)\,\rho_s c_s,\qquad \lambda_{\mathrm{eff}} \approx \lambda_w^{\,n}\,\lambda_s^{\,1-n} \]REV explorer
Drag the windowThree fields, three balance laws
Each process has a conserved quantity, a state variable that measures it, and a flux law that says how it moves. Water mass is measured by pore pressure and moves by Darcy's law. Heat is measured by temperature and moves by Fourier conduction plus whatever the water carries. Momentum is measured by displacement and strain, and is balanced by stress. Taken alone, each is a textbook problem; the couplings in §3 are what make the ground interesting.
Darcy flow
Pressure in excess of hydrostatic drives water through the pore network. The specific discharge q is proportional to the head gradient and to the permeability k of the medium divided by the viscosity μ of the water.
Conduction and advection
Heat diffuses through grains and water together, and is carried along by any water that flows. The Péclet number compares the two. In clays it is practically zero; in a gravel aquifer it can be large.
Effective stress
The skeleton only feels the part of the total stress that the pore water does not carry. Raise the pore pressure at constant total stress and the effective stress drops: the Mohr circle slides toward the failure envelope without changing size.
Six couplings
Each field enters the other two balance equations somewhere. That gives six directed couplings, of very unequal strength. Two are so strong that no geotechnical calculation can ignore them (pore pressure on effective stress, and volume change on pore pressure). Two depend on the material and the time scale. One is almost always dropped.
Select an arrow to see the mechanism, the term it adds to the equations, and a feel for its size.
| Coupling | Mechanism | Enters through | Typical strength |
|---|---|---|---|
| T → H | Thermal expansion of water versus skeleton; viscosity falls with temperature | βζ ∂tT in the mass balance; μ(T) in Darcy's law | Strong in low-permeability media |
| H → T | Flowing water carries heat | ρwcw q·∇T in the energy balance | Negligible in clay, dominant in aquifers |
| T → M | Thermal strain of the skeleton; thermal stress when restrained | αTΔT I in the stress–strain law | Strong |
| M → T | Thermoelastic heating, frictional dissipation | Source term in the energy balance | Almost always neglected |
| H → M | Pore pressure carries part of the total stress | α p I in the effective stress | Strong, always |
| M → H | Volume change stores or expels water; strain alters permeability | α ∂tεv in the mass balance; k(ε) | Strong in soft soils and fractured rock |
The governing equations
Here is the full system for a saturated, linearly thermo-poroelastic medium at small strain, in the form used by Biot, McTigue and Coussy. Sign convention in this section: stress positive in tension and pore pressure positive in compression, the continuum-mechanics habit, so the total stress is σ = σ′ − α p I. §2 and §5 use the geotechnical convention, compression positive, where the same law reads σ′ = σ − α p. Hover or tap any term to see what it does and which coupling it carries.
Three diffusivities and one pressurization coefficient summarise how the system behaves. Their ratios, not their absolute values, decide which couplings matter.
\[ \kappa = \frac{\lambda_{\mathrm{eff}}}{(\rho c)_{\mathrm{eff}}},\qquad c = \frac{k}{\mu\,S},\quad S = \frac{\alpha^2}{K_d} + \frac{\alpha - n}{K_s} + \frac{n}{K_w},\qquad \Lambda = \frac{n\,(\beta_w - \beta_s)}{S},\qquad \mathrm{Pe} = \frac{\rho_w c_w\, q\, L}{\lambda_{\mathrm{eff}}} \]Consolidation
The oldest coupled problem in geotechnics. Load a saturated clay layer and the water cannot leave at once, so at first it carries the load as excess pore pressure and the skeleton feels nothing. As water drains toward the free surface the load transfers to the skeleton, which compresses, and the surface settles. Terzaghi wrote this in 1923 as a diffusion equation for the excess pressure u; it is the M → H and H → M couplings acting together, with the mechanics eliminated.
\[ \frac{\partial u}{\partial t} = c_v\,\frac{\partial^2 u}{\partial z^2},\qquad c_v = \frac{k\,E_{\mathrm{oed}}}{\mu},\qquad T_v = \frac{c_v\,t}{H^2} \]The solution for a layer of thickness H drained at the top and sealed at the bottom is a sine series in depth that decays exponentially in the dimensionless time Tv. The average degree of consolidation U is the fraction of the final settlement reached.
\[ \frac{u}{u_0} = \sum_{m=0}^{\infty} \frac{2}{M_m}\,\sin\!\left(M_m \frac{z}{H}\right) e^{-M_m^2 T_v},\qquad U = 1 - \sum_{m=0}^{\infty}\frac{2}{M_m^2}\,e^{-M_m^2 T_v},\qquad M_m = \tfrac{\pi}{2}(2m+1) \]Terzaghi's isochrones
Analytic series, 400 termsThermal pressurization
Heat a saturated element of clay and forbid it to drain. The water wants to expand by βwΔT, but the pore space that holds it only grows by about βsΔT, an order of magnitude less. The mismatch must be taken up by compressing the water and pushing the skeleton apart, and both cost pressure. Solving the mass balance of §4 for an undrained element at constant total stress gives the undrained pressurization coefficient Λ, the pressure rise per kelvin.
\[ \Lambda = \left.\frac{\partial p}{\partial T}\right|_{\text{undrained},\,\sigma} = \frac{n\,(\beta_w - \beta_s)}{\dfrac{\alpha^2}{K_d} + \dfrac{\alpha-n}{K_s} + \dfrac{n}{K_w}} \]Stiff, low-porosity rock has the largest Λ because nothing yields to relieve the pressure. βw itself more than doubles between 20 and 60 °C, which is why heating tests pressurize faster as they go.
Undrained heating
Λ across materialsHeating a point in the ground
In the ground, drainage competes with heating. Heat spreads at the thermal diffusivity κ; excess pressure dissipates at the hydraulic diffusivity c. Booker and Savvidou solved the case of a constant point heat source of power Q in an infinite saturated medium in closed form. The temperature is the familiar continuous-source solution; the pressure is the difference of two such solutions, one spreading at κ and one at c.
\[ \Delta T(r,t) = \frac{Q}{4\pi\lambda r}\,\operatorname{erfc}\!\frac{r}{2\sqrt{\kappa t}},\qquad p(r,t) = \frac{\Lambda\,Q}{4\pi\lambda r}\;\frac{\kappa}{\kappa - c}\left[\operatorname{erfc}\frac{r}{2\sqrt{\kappa t}} - \operatorname{erfc}\frac{r}{2\sqrt{c t}}\right] \]If c ≪ κ the pressure front lags the heat front: pressure rises almost undrained, peaks, then bleeds away over the hydraulic time scale. If c ≫ κ the bracket stays tiny and pressure never accumulates. The ratio c/κ is the single most useful number for judging whether a heated ground will pressurize.
Point heat source
Booker & Savvidou, 1985Live simulation
A horizontal heater, 4 m by 1 m in section, buried in a saturated ground 24 m wide and 15 m high with groundwater flowing left to right. Temperature obeys advection–diffusion with the heater as a source; pore pressure diffuses with a source Λ ∂tT. The far boundary stays at ambient temperature and is drained. It is the §4 system with the mechanics eliminated, solved by explicit finite differences on 96 × 60 cells of 0.25 m, in your browser, in real time.
Watch the pressure field: it appears with the heat, but it is governed by the hydraulic diffusivity, so in clay it lingers long after the temperature has settled, and in sand it never shows up at all.
Heater in a saturated ground
Explicit FD · upwind advectionScales and where it matters
Every diffusive process has one time scale, t ≈ L²/D. Because κ is nearly the same for all geomaterials while c spans twelve orders of magnitude, the thermal line is a fixed reference and the hydraulic lines fan out around it. Where a hydraulic line sits above the thermal one, heat outruns drainage and the ground pressurizes; where it sits far below, the ground stays drained and heat and water decouple.
Diffusion time against length
t = L² / DDeep geological disposal of nuclear waste
Canisters at 60–100 °C in clay or crystalline host rock at 400–800 m. Thermal pressurization can reach several megapascals in the first decades, reducing effective stress in the very barrier that is meant to stay intact; the bentonite buffer swells, dries and resaturates around it.
Geothermal reservoirs
Cold water injected into hot fractured rock contracts the rock around the fractures, opening apertures and raising permeability, while the cooling front and the pressure front move at very different speeds. The heat is carried out by the flow, so Pe is large.
Injection-induced seismicity and CO₂ storage
Injecting fluid raises pore pressure over kilometres and years. Faults that were stable at the in-situ effective stress can be brought to failure by a pressure rise of a fraction of a megapascal, exactly the Mohr-circle shift of §2, with thermal contraction from cold injectate adding to it.
Freezing ground and permafrost
Phase change of pore water adds latent heat, expansion on freezing and a permeability that collapses as ice forms. Thaw releases water faster than it can drain, so the ground loses strength: thaw consolidation is Terzaghi's problem with a moving boundary.